Skills and Knowledge:

Some Words About Me:

"Google My Teacher!!!"

At the moment I decided to change my field of activity, I have been working for many years in advertising and printing as a manager. The world of IT has always been interesting, but it seemed inaccessible - all fears are in my head :), you have to learn and code !! And I think everything will work out!

Courses and Experience:

I study it myself, I'm interested in the Front-End Developer and Manual QA direction. Studied programming basics: HTML5, CSS, JavaScript, Python, SQL.:

* RS Schools Course «JavaScript/Front-end. Stage 0»;

* RS Schools Course «JavaScript/Front-end. Stage 1»;

* JavaScript on learnjavascript.ru, WebDev Alex Lushchenko, developer.mozilla.org, itgid.info;

* HTML Academy, Codecademy, WebForMySelf;

* Prometheus - Basics of software testing;

* QAtestlab - FUNDAMENTALS OF TESTING SOFTWARE (Certificate №2364.);

* 'Hamsters' project for joint testing of projects to share experiences. Tested Mobile appl. magnit.ru;

* 'Hamsters' tested web: makestoryboard.com;

* Tested the CRM system of orders at the place of work.


React - тестовое задание

Weather&ToDo

JS/HTML/CSS:

hslider

JS/HTML/CSS:

clikit

Languages:

*English \- Intermediate

*Russian \- Native

*Ukrainian \- Intermediate

Code example:

Move the first letter of each word to the end of it, then add “ay” to the end of the word. Leave punctuation marks untouched. Example pigIt('Pig latin is cool'); // igPay atinlay siay oolcay The returned format must be correct in order to complete this challenge. Don’t forget the space after the closing parentheses!


                function pigIt(str){
                  let strNew = []
                  str = str.split(' ')
                  str.forEach( item =>{
                    if (item.match( (/[^A-Za-z0-9\s]/g))){
                      strNew.push(item)
                        }
                        else {
                            strNew.push(item.slice(1)
                                + item.slice(0,1)+'ay')
                        }
                    })
                    return strNew.join(' ')
                }